Karolina Muchova vs Elina Avanesyan – Round of 16 – Preview & Prediction | 2023 French Open
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THE FACTS
When is Karolina Muchova vs Elina Avanesyan on and what time does it start? Karolina Muchova vs Elina Avanesyan will take place on Sunday 4th June, 2023 – not before 12:00 (UK)
Where is Karolina Muchova vs Elina Avanesyan taking place? Karolina Muchova vs Elina Avanesyan will take place at Stade Roland Garros in Paris, France
What surface is Karolina Muchova vs Elina Avanesyan being played on? Karolina Muchova vs Elina Avanesyan will take place on an outdoor clay court
Where can I get tickets for Karolina Muchova vs Elina Avanesyan? Visit this link for the latest ticket information for Karolina Muchova vs Elina Avanesyan
What channel is Karolina Muchova vs Elina Avanesyan on in the UK? Eurosport have the rights to the French Open in the UK
Where can I stream Karolina Muchova vs Elina Avanesyan in the UK? discovery+ subscribers can stream Karolina Muchova vs Elina Avanesyan live while the match can be streamed on Eurosport Player and Amazon Prime Video if it is televised
THE PREDICTION
20-year-old Elina Avanesyan will break the top 100 for the first time on tour after an excellent comeback over fellow youngster Clara Tauson. The Russian scraped through to the first round as a lucky loser before an excellent three-set victory over 12th seed Belinda Bencic, who was clearly not yet fit enough to compete here in Paris. World number 43 Karolina Muchova can move back inside the top 30 with one more win here as she continues to repair her ranking from a long injury lay-off last season. The Czech set a career-high WTA world ranking of 19th as recently as 2021 and she is playing like it again with some confidence restored in her body. An upset over Maria Sakkari in the first round was impressive but her straight-sets win over clay-court specialist Irina-Camelia Begu on Friday is perhaps even more convincing of her credentials as an outside title threat. Back Muchova to win outright inside an accumulator or in straight sets on its own.
